Page 144 - aljaber
P. 144
@ @QSQ@ @pý†bɾa@ @
2x2 − 3x = 4 βα ()
4x2 − 3x − 3 = 0 ( ) :11
4x2 + 3x − 2 = 0 ( )
βα
3x 2 − 2x − 2 = 0
4x2 + 3x − 3 = 0 ( )
4x2 − 3x + 2 = 0 ( )
nm ( )
6x 2 + 10x − 25 = 0 ( ) : n− 1 m−1
mn
6x 2 − 10x − 25 = 0 ( )
6x 2 − 10x + 25 = 0 ( ) 6x 2 + 10x + 25 = 0 ( )
4x2 − 3x − 3 = 0 βα ( )
)
: β3 α3
64x 2 − 135x + 27 = 0 ( ) 64x 2 + 135x − 27 = 0 ( )
64x 2 + 135x + 27 = 0 ( ) 64x 2 − 135x − 27 = 0 ( )
x 2 + mx + n = 0 [AMC12B 2005] (
n≠0 m≠0 x 2 + px + m = 0
8() 4( ) :n p≠0
p 1 ()
2( )
[AHSME 1954] ( )
1 a(b − c)x2 + b(c − a)x + c(a − b) = 0
a(b − c) ( ) b(c − a) ( )
c(a − b) a(b − c)