Page 150 - Fixtures
P. 150
@ @QSU@ @æa@paˆ@pþàbÉà@ @
(1 − 2x)5 = C (5, 0)(1)5 + C (5,1)14(−2x)1 + C(5,2)13(−2x)2
+ C (5, 3)12(−2x)3 + C (5, 4)1(−2x)4 + C (5, 5)(−2x)5
= 1 − 10x + 40x 2 − 80x 3 + 80x 4 − 32x 5
x 3 , .(x + 2x2)2 = x2 + 4x 3 + 4x4 ,
. 4x 3 ,−10x 3 (x + 2x2)2(1 − 2x)5
.−6 x 3 .−10x 3 + 4x 3 = −6x 3
n + 1 (x + y)n
Tk +1 = C (n,k)x n−kyk
. 3x − 4 14 ()
x2
.Tk +1 = C (14,k)(3x)14−k −4 k
x2
k =6
.T7 = C (14, 6)(3x )8 −4 6 = 38 × 46 ×C (14, 6)x −4
x2
. x 2 + 4 12 x6 ()
x
.Tk +1 = C (12, k )(x 2 )12−k 4 k = C (12,k)× 4k × x 24−3k
x