Page 160 - Fixtures
P. 160

@ @QTU@                              @æa@paˆ@pþàbÉà@                                     @

                                               10 i                        [MAΘ 1992] (     )
                                                                           [MAΘ 1992] (     )
                                              ∑ ∑C(i,k)
                                                                                            )
                                              i=1 k =1                                      )

                44C(45, 0) + 43C(45,1) + 42C(45,2) +                                        )
                                                                                            )
         .(2a −b + 3c − 5d)10                                 + 0C(45, 44) −C(45, 45)       )

                                                                                      (

                                                                                n(

C(n,1) + 3C(n, 3) + 5C(n,5) + + (n − 1)C(n,n − 1)

                                                                                = n2n−2

                         .   n                          −  1)  =    C (2n,n  −  1)       (

                            ∑C (n,k)C(n,k
                            k =1

                                     ∑. n k 2C (n,k) = n(n + 1)2n−2                      (

                                         k =1

                                                                       [AIME 1992] (

                                                     3:4:5

                                                            n                            ()
                                                                                         ()
                                                         ∑ iC (i − 1,k − 1)              ()
                                                                                         ()
                                                        . i=k

                                                                C (n, k )

                         .   k       (n,  i  )C  (n  −  i, k  − i)  =  2kC (n,k)

                            ∑C
                            i=0

                .   n       (n,   k  )C  (n,  n  −   k  +  1)  =  C (2n,n    +  1)

                   ∑C
                   k =1

         .[( )                       :            20

                                                 ∑C (20,k)C (20,k − 1)]
                                                 k =1
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