Page 109 - aljaber
P. 109
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x = 12 ± −16 .
2
.
.255 ( )
. x +2 .x
x(x + 2) = 255
x 2 + 2x − 255 = 0
(x + 17)(x − 15) = 0
.x = 15 x = −17
.17 15 −15 −17
ABCD ()
()
.
BCXY ADXY
x AB . AB . ABCD
AD
.1+ 5 1 AD
2
