Page 118 - aljaber

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−1 ± 1 7 ( ) 1±1 7 ()

22 22

−1 ± 7 ( ) 1± 7 ( )

x 2 + 4x + m = 0 m ()

1 () 1( ) 5( ) 4 ()

5 4
α a≠0
ax2 − 6x + a − 2 = 0 ()

a = 4 a = −2 ( ) a 2α )
a = −4 a = 2 ( )
a = 4 a =2 ()
12 a = −4 a = −2 ( )

(
.

12
0.2

.

2 ( ) 11 ( ) 1 ( ) 1()

2 2

()

8 . 1600