Page 214 - aljaber

RPQ@ @†ì‡¨a@pa rØ

.r(x) = x − 1 .a = 1 b = −1

.α + β = γ γβα :( ) ()

α + β + γ = −(−6) = 6

αβγ = −30

.γ = 3 .2γ = 6

. β = −10

α

α − 10 + 3 = 6
α

α − 10 − 3 = 0
α

α2 − 3α − 10 = 0

(α − 5)(α + 2) = 0

. α = 5 α = −2

α=0 ) α≠0 .−2 −2, 3, 5

f (x) .( 0 = −30

. f (x) x +1 x −1 :( ) ( )
)
(x − 1)(x + 1) = x 2 − 1

x2 −1 f (x)

f (x) = (x2 − 1)(x2 − 7x + 12) (
= (x 2 − 1)(x − 3)(x − 4)

.7 4 3

:( )