Page 214 - aljaber
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RPQ@ @†ì‡¨a@pa rØ
.r(x) = x − 1 .a = 1 b = −1
.α + β = γ γβα :( ) ()
α + β + γ = −(−6) = 6
αβγ = −30
.γ = 3 .2γ = 6
. β = −10
α
α − 10 + 3 = 6
α
α − 10 − 3 = 0
α
α2 − 3α − 10 = 0
(α − 5)(α + 2) = 0
. α = 5 α = −2
α=0 ) α≠0 .−2 −2, 3, 5
f (x) .( 0 = −30
. f (x) x +1 x −1 :( ) ( )
)
(x − 1)(x + 1) = x 2 − 1
x2 −1 f (x)
f (x) = (x2 − 1)(x2 − 7x + 12) (
= (x 2 − 1)(x − 3)(x − 4)
.7 4 3
:( )