Page 215 - aljaber

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p f (x) p:

q

. 3 q 42

. β = −3 α = 2

3

1 + 1 = 3−1 = 9−2 = 7
αβ 23 6 6

. x −7 7:

x −7 f (x)

( )f (x) = (x − 7) 3x2 + 7x − 6

= (x − 7)(3x − 2)(x + 3)

. β = −3 α = 2

3

:

7 + α + β = 14 ⇒ α + β = 14 − 7 = − 7
3 33
7αβ = − 42 ⇒
3 αβ = −2

. 1 + 1 = β + α = −7 / 3 = 7
α β αβ −2 6

:( ) ( )

f  x  = 2x 2 + x + 3 = 50  x 2 + 5  x  + 3
5 5 5

f (x) = 50x 2 + 5x + 3
f (5x) = 1250x2 + 25x + 3