Page 196 - aljaber
P. 196
QXS@ @†ì‡¨a@pa rØ
. α1α2α3 = −d α1α2 = c α3 = 3
12 4
.d = −3c .c = − d
4 12
. x 2 − 3x + 2 f (x ) = x 90 .d = −3 )
c
(
q(x) x 2 − 3x + 2 f (x) r(x) = ax + b
.
( )f (x) = x 90 = x2 − 3x + 2 q(x) + (ax + b)
= (x − 1)(x − 2)q(x) + (ax + b)
f (1) = 1 = 0 + a + b
f (2) = 290 = 0 + 2a + b
a +b = 1 .b = 2 − 290
2a + b = 290
.a = 290 − 1
.r(x) = (290 − 1)x + (2 − 290 )
[Factorization of Polynomials] (.)
)
