Page 44 - Engineering

‫ﺍﳌﺴﺘﻘﻴﻤﺎﺕ ﻭﺍﻟﺰﻭﺍﻳﺎ ‪٣١‬‬

‫)‪ [AUST.MC 1982] (١٦‬ﰲ اﻟﺸﻜﻞ اﳌﺮﻓﻖ‪ ،‬اﻟﻨﻘﻄﺔ ‪ T‬واﻗﻌﺔ ﻋﻠﻰ اﳌﺴﺘﻘﻴﻢ‬
‫‪ .PQ‬ﻣﺎ ﻗﻴﺎس اﻟﺰاوﻳﺔ ‪ PTS‬؟‬

‫‪S‬‬

‫)د( ‪95°‬‬ ‫‪P‬‬ ‫‪R‬‬ ‫)أ( ‪80°‬‬
‫‪70°‬‬
‫)ج( ‪90°‬‬
‫‪30° Q‬‬
‫‪T‬‬

‫)ب( ‪85°‬‬

‫اﻟﺤﻞ‪ :‬اﻹﺟﺎﺑﺔ ﻫﻲ )أ(‪:‬‬

‫‪PTS = 180° − (30° + 70°) = 180° − 100° = 80° .‬‬

‫)‪ [AUST.MC 1981] (١٧‬ﻗﻴﻤﺔ ‪ x‬ﰲ اﻟﺸﻜﻞ اﳌﺮﻓﻖ ﺗﺴﺎوي‬

‫)د( ‪220°‬‬ ‫)ج( ‪110°‬‬ ‫)ب( ‪70°‬‬ ‫)أ( ‪20°‬‬

‫‪140°‬‬
‫‪x° x°‬‬

‫اﻟﺤﻞ‪ :‬اﻹﺟﺎﺑﺔ ﻫﻲ )ج(‪ :‬ﲟﺎ أن ‪ x° + x° + 140° = 360°‬ﻓﺈن ‪.2x = 220°‬‬
‫و‪‬ﺬا ﻓﺈن ‪.x = 110°‬‬

‫)‪ [AUST.MC 1979] (١٨‬ﰲ اﻟﺸﻜﻞ اﳌﺮﻓﻖ ‪ ADC‬ﻣﺴﺘﻘﻴﻢ‪ .‬ﻗﻴﺎس اﻟﺰاوﻳﺔ‬

‫‪ BDC‬ﻳﺴﺎوي‬

‫)د( ‪100°‬‬ ‫)ج( ‪80°‬‬ ‫)ب( ‪50°‬‬ ‫)أ( ‪20°‬‬