Page 46 - Engineering
P. 46
ﺍﳌﺴﺘﻘﻴﻤﺎﺕ ﻭﺍﻟﺰﻭﺍﻳﺎ ٣٣
اﻟﺤﻞ :اﻹﺟﺎﺑﺔ ﻫﻲ )أ( x = 110° :ﺑﺎﻟﺘﻘﺎﺑﻞ ﺑﺎﻟﺮأس .إذن،
.y = 180° − x = 70°
) (٢١ﻗﻴﻤﺔ x + yﰲ اﻟﺸﻜﻞ اﳌﺮﻓﻖ ﺗﺴﺎوي
)د( 180° )ج( 160° )ب( 140° )أ( 120°
E D
C
F 80° y°
A x ° 140°
B
اﻟﺤﻞ :اﻹﺟﺎﺑﺔ ﻫﻲ )د( :ارﺳﻢ ﻣﺴﺘﻘﻴﻤﺎً ﻣﻮازﻳﺎً ﻟﻠﻤﺴﺘﻘﻴﻢ ABCﻣﻦ اﻟﻨﻘﻄﺔ F
وﻟﻴﻜﻦ .FG
E D
F G
AB C
ﻟﺪﻳﻨﺎ
)زاوﻳﺔ ﻣﺴﺘﻘﻴﻤﺔ( x = 180 − 140 = 40°
)ﺑﺎﻟﺘﺒﺎدل اﻟﺪاﺧﻠﻲ( GFB = ɵx = 40°
إذن .GFE = 80 − 40 = 40° ،ﻣﻦ ذﻟﻚ ﳒﺪ أن .y = 180 − 40 = 140°
وﺬا ﻳﻜﻮن .x + y = 40 + 140 = 180°
) (٢٢ﻗﻴﺎس اﻟﺰاوﻳﺔ ɵxﰲ اﻟﺸﻜﻞ اﳌﺮﻓﻖ ﺗﺴﺎوي
)د( 130° )ج( 120° )ب( 110° )أ( 70°
