Page 92 - Engineering

‫‪٧٩‬‬ ‫ﺍﳌﺜﻠﺜﺎﺕ‬

‫)د( ‪70°‬‬ ‫ﻣﺴﺎﺋﻞ ﻣﺤﻠﻮﻟﺔ‬

‫)‪ [Anst.MC 1984] (١‬ﻗﻴﻤﺔ ‪ x‬ﰲ اﻟﺸﻜﻞ اﳌﺮﻓﻖ ﺗﺴﺎوي‬

‫)ج( ‪60°‬‬ ‫)ب( ‪50°‬‬ ‫)أ( ‪30°‬‬

‫‪P‬‬
‫‪x‬‬

‫‪120° 130°‬‬
‫‪QR‬‬

‫اﻟﺤﻞ‪ :‬اﻹﺟﺎﺑﺔ ﻫﻲ )د(‪PQR = 180 − 120 = 60° :‬‬
‫‪ .PRQ = 180 − 130 = 50°‬إذن‪.ɵx = 180 − (60 + 50) = 70° ،‬‬

‫)‪ [Aust.MC 1983] (٢‬ﻗﻴﻤﺔ ‪ x‬ﰲ اﻟﺸﻜﻞ اﳌﺮﻓﻖ ﺗﺴﺎوي‬

‫)د( ‪145°‬‬ ‫)ج( ‪142°‬‬ ‫)ب( ‪108°‬‬ ‫)أ( ‪72°‬‬

‫‪xA‬‬

‫‪35°‬‬ ‫‪107°‬‬
‫‪B‬‬ ‫‪C‬‬

‫اﻟﺤﻞ‪ :‬اﻹﺟﺎﺑﺔ ﻫﻲ )ب(‪ .ACB = 180 − 107 = 73° :‬وﻣﻦ ﰒ ﻓﺈن‬

‫‪.ɵx = ABC + ACB = 35 + 73 = 108°‬‬

‫)‪ [Aust.MC 1982] (٣‬ﻗﻴﺎس اﻟﺰاوﻳﺔ ‪ QPS‬ﰲ اﻟﺸﻜﻞ اﳌﺮﻓﻖ ﻳﺴﺎوي‬

‫)د( ‪105°‬‬ ‫)ج( ‪96°‬‬ ‫)ب( ‪90°‬‬ ‫)أ( ‪60°‬‬